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Enter an equation in standard form for the line.
Slope is -4, and (-9, -12) is on the line.

Sagot :

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Answer:

[tex] 4x + y +48=0[/tex]

Step-by-step explanation:

We are here given the slope of the line and one point through which it passes . The slope of the line is -4 and the point is (-9,-12) .

Here we can use the point slope form of the line as ,

[tex]\sf\longrightarrow y-y_1 = m(x-x_1) [/tex]

Substitute the respective values ,

[tex]\sf\longrightarrow y - (-12) = -4\{ x -(-9)\} [/tex]

Simplify LHS and RHS ,

[tex]\sf\longrightarrow y + 12 = -4( x +9) [/tex]

Open the brackets in RHS ,

[tex]\sf\longrightarrow y + 12 = -4x -36 [/tex]

Add 36 and 4x to both sides ,

[tex]\sf\longrightarrow \underline{\boxed{\orange{\sf 4x + y + 48 =0}}}[/tex]

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