Answered

IDNLearn.com connects you with a community of experts ready to answer your questions. Join our knowledgeable community to find the answers you need for any topic or issue.

A 152 g sample of ice at –37oC is heated until it turns into liquid water at 0oC. Find the change in heat content of the system.

Sagot :

Answer:

What do you mean? The Q is a bit vague

Laxbro2007idn

Answer:

The change in heat content is

26,000 J

.

Explanation:

Use the following equation:

Q

=

m

c

Δ

T

,

where

Q

is heat energy in Joules,

m

is mass,

c

is specific heat capacity, and

Δ

T

is change in temperature,

(

T

final

−

T

initial

)

.

Organize your data

.

Given/Known

m

=

445 g

c

ice

=

2.03 J

g

⋅

∘

C

T

initial

=

−

58

∘

C

T

final

=

−

29

∘

C

Δ

T

=

−

29

∘

C

−

(

−

58

∘

C

)

=

29

∘

C

Explanation:

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.