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An archer stands at rest on frictionless ice; his total mass including his bow and quiver of arrows is 60.00 kg. He then fires a 0.030 0-kg arrow at 50.0 m/s at an angle of 30.0° above the horizontal. If it takes 650N of force to break the ice and the arrow leaves the bow in 10ms, does the archer fall into the frozen lake?

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Sagot :

Answer:

Explanation:

Impulse results in change of momentum

FΔt = mΔv

F = 0.030(50.0 - 0) / 0.010 = 150 N

The vertical portion of that force adds to his weight on the ice

Fmax = 60.00(9.81) + 150sin30 = 663.6 N

As this is above the ice strength, He takes a cold dip.

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