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Sketch one cycle of y = sin 2q.

Sagot :

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Answer:

y = sin ( 2 x )

graph{sin(2x) [-10, 10, -5, 5]}

Step-by-step explanation:

y = − sin ( 2 x )

x = 0 , y = 0

x = π 4 , y = − 1

x = π 2 , y = 0

x= ( − π 4 ) , y = 1  

With these values, we can plot the graph.

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