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The length of a rectangle is 3 feet more than 5 times its width. The perimeter of the rectangle is 42 feet.

Write an equation that can be used to find the width (w) of the rectangle and solve the equations


Sagot :

42 = 2(W+L)

21= (W+L)

L= 3+5W)

21= W +(3+5W)

21= 3+6W

21-3=6W

18=6W

W=18/6

=3

Answer:

w = PERIMETER/2 - LENGTH

w = 42/2 - (3+5w)

PS. I THINK THIS IS RIGHT. NOT TOO SURE, BUT MOST LIKELY.