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A 25 kg chair initially at rest on a horizontal floor requires a 365 N horizontal force to set it in motion. Once the chair is in motion, a 327 N horizontal force keeps it moving at a constant velocity.

a)Find the coefficient of static friction between the chair and the floor.
b)Find the coefficient of kinetic friction between the chair and the floor.

Sagot :

Answer:

Here's what you know, m=25 kg, Ff=365 N, g=9.8 m/s^2, use the formula Fg = mg, Fg =25*9.8, Fg =245 N, then use the formula Ff <= ตsFn, 365=245ตs, solve for ตs,  ตs=1.5.

Here's what ya know, m=25 kg, Ff=327 N, the normal force of gravity will be the same as in part A.  Now use the formula Ff = µkFn, 327=245 µk, solve for µk, µk=1.3.

Explanation:

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