ShadowWolfieidn
Answered

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Solve the equation with special factors. (Please show all steps)
16q^2 - 81 = 0

Sagot :

Nikolavisinoskiidn

Answer: [tex]q=\frac{\sqrt{81}}{16}[/tex]

Step-by-step explanation:

[tex]16q^2-81=0\\16q^2=0+81=81\\16q=\sqrt{81} \\q=\frac{\sqrt{81}}{16}[/tex]

Answer:

q = ± [tex]\frac{9}{4}[/tex]

Step-by-step explanation:

16q² - 81 = 0 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

16q² - 81 = 0

(4q)² - 9² = 0

(4q - 9)(4q + 9) = 0

Equate each factor to zero and solve for q

4q - 9 = 0 ⇒ 4q = 9 ⇒ q = [tex]\frac{9}{4}[/tex]

4q + 9 = 0 ⇒ 4q = - 9 ⇒ q = - [tex]\frac{9}{4}[/tex]

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