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Drag each tile to the correct box. Consider the given functions f, g, and h.

h(x)=x²+x-6

Place the tiles in order from least to greatest according to the average rate of change of the functions over the interval [0,3]

Sagot :

IIitzAryanIIidn

Answer:

g, f, h

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]

So, in your case, we want to compute the quantity

[tex]\dfrac{f(3)-f(0)}{3}[/tex]

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

[tex]\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3[/tex]

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

[tex]\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}[/tex]

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

h(3)=3^2+3-6=9+3-6=6,[tex]\quad h(0)=0^2+0-6=-6[/tex]

And so the average rate of change is

[tex]\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4[/tex]

Ba100609idn

Answer:

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Step-by-step explanation:

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