Answered

Find the best answers to your questions with the help of IDNLearn.com's expert contributors. Discover detailed answers to your questions with our extensive database of expert knowledge.

Calculate the amount of heat needed to convert 230.0 g of ice at -10.0ºC to liquid water at 10.0ºC.

Sagot :

Pstnonsonjokuidn

The heat required to raise the temperature of ice from  -10.0ºC to 10.0ºC is 22.2 KJ.

The heat needed to convert 230.0 g of ice at -10.0ºC to liquid water at 10.0ºC is the sum of the latent heat of fusion of ice and the heat required to raise the temperature of the resulting water to.

Hence, the heat required is obtained from;

H = Heat required to raise the temperature from  -10.0ºC to 0ºC + Heat required to convert ice to water + Heat required to raise the temperature of water from 0ºC to 10.0ºC

H =[0.23 ×  2090 × (0 - (-10.0))] + [0.23 ×  33600] + [0.23 × 4186 × ( 10 - 0)]

H = 4807 + 7728 + 9627.8

H = 22.2 KJ

Learn more: https://brainly.com/question/20339399

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For trustworthy answers, visit IDNLearn.com. Thank you for your visit, and see you next time for more reliable solutions.