Answered

Join IDNLearn.com and start exploring the answers to your most pressing questions. Our Q&A platform offers reliable and thorough answers to help you make informed decisions quickly and easily.

According to the Rational Root Theorem, the following are potential roots of f(x) = 60x2 – 57x – 18.

Negative six-fifths, Negative one-fourths, 3, 6

Which is an actual root of f(x)?

Sagot :

27tristenjonesidn

Answer:As for Rational Root Theorem, we substitute the given choices in the equation and if the value of f(x) is equal to 0 then, the certain choice is a root of the equation.

(1)     -6/5 :    f(x) = 60(-6/5)^2 - 57(-6/5) - 18  = 136.8

(2)     -1/4:     f(x) = 60(-1/4)^2 - 57(-1/4) - 18 = 0

(3)         3:     f(x) = 60(3)^2 - 57(3) - 18 = 351

(4)         6:     f(x) = 60(6)^2 -57(6) - 18 = 1800

Thus, the answer is the second choice.

Step-by-step explanation:

Quint1836idn

Answer:

B -1/4

Step-by-step explanation:

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.