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A book is pushed off the edge of a table. At what point during the fall will the potential and kinetic energy be equal?

Sagot :

Answer:

KE = PE at half the table Height:

Explanation

AT ANY POINT IN THE BOOK'S FALL,

TOTAL E = PE +KE

THE TOTAL E IS CONSTANT

Before the book is pushed off, the total energy is potential

TOT E=PE =MGH

BEFORE THE BOOK HITS THE GROUND, THE TOTAL E IS KINETIC

TOT=KE = MVXV/2

WHEN KE = PE

KE+PE = MGH (STARTING ENERGY SINCE E IS CONSERVED)

OR PE+ PE = MGH

OR MGH' + MGH' =MGH

OR 2H' =H

H' (NEW HEIGHT) =H/2

Adefioyelaoyeidn

The point during a fall where  the potential and kinetic energy be equal will

be at the midpoint of the initial height.

The object first of all possesses potential energy when at rest and then

kinetic energy when in motion.

When KE = PE

We can deduce that KE+PE = MGH and  PE+ PE = MGH

this means that MGH + MGH=MGH and  2H =H

The new height will then be H =H/2  which is the midpoint of the initial

height.

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