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What is the equation of a line that passes through (-3, 2) and (2, -3)?
An equation that passes through (-3,2) and (2,-3) is y=-x-1
It is because the slope is m=y2-y1/x2-x1= -3-2/2-(-3) = -3-2/2+3 =-5/5=-1
Now that we know what the slope is, we have to find the y-intercept using the common equation y=mx+b so pick a point (I’m gonna pick (2,-3)) so y=Mx +b = -3=(-1)(2) +b. After solving that you should get your b to equate to -1
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