Rosie0905idn
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A line passes through the point (-6, -8) and has a slope of 5/2 write an equation in slope intercept form for this line.

Sagot :

Reinhard10158idn

Step-by-step explanation:

the slope intercept form in general is

y = ax + b

a is the slope, b is the y-intercept (when x=0).

we have already the slope. with that it looks like

y = 5/2 × x + b = 5x/2 + b

and b we get by using the circuses of the given point as x and y :

-8 = 5×-6/2 + b = 5×-3 + b = -15 + b

7 = b

so, all in all, the line equation is

y = 5x/2 + 7

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