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Calculate the net torque about point O for the two forces applied as in the figure below. The rod and both forces are in the plane of the page. Let F1=7.80N and F2=11.0N. Take counterclockwise torques to be positive.
A horizontal rod. Point O is marked at its left end. The rod is subjected to two forces. Force F subscript 1 acts vertically downward on the right end of the rod. Force F subscript 2 acts on a point of the rod 2.00 meters from its left end and 3.00 meters from its right end. Force F subscript 2 points upward and to the left making an angle of 30.0 degrees with the rod.


Sagot :

The net torque about point O for the two forces applied as in the figure below is 17.4Nm

Find the diagram to the question attached

Given the following parameters

F1 = 7.80N

F2=11.0N

Taking the force along the vertical;

τ₂ = 7.80sin30(2.0)

τ₂ = 15.6Nm

For the other force along the vertical;

τ₁ = 11.0 * 3

τ₁ = 33Nm

Net torque is expressed as =  33Nm -  15.6Nm

Net torque = 17.4Nm

Hence the net torque about point O for the two forces applied as in the figure below is 17.4Nm

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