Connect with experts and get insightful answers on IDNLearn.com. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.
Sagot :
The force acting on the log as it rolls down a hill is equal to 104.5 Newton.
Given the following data:
- Initial velocity = 1.3 m/s
- Time = 4 seconds
- Final speed = 3.2 m/s
- Mass = 220 kg
To determine the force acting on the log:
First of all, we would calculate the acceleration of the log by using this formula:
[tex]Acceleration = \frac{V\;-\;U}{t} \\\\Acceleration = \frac{3.2\;-\;1.3}{4} \\\\Acceleration =\frac{1.9}{4}[/tex]
Acceleration = 0.475 [tex]m/s^2[/tex]
Now, we can solve for the force by applying Newton's Second Law of Motion:
[tex]Force = mass \times acceleration[/tex]
[tex]Force = 220 \times 0.475[/tex]
Force = 104.5 Newton
Read more here: https://brainly.com/question/24029674
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.