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Given f(x)= 17 – x^2, what is the average rate of change in f(x) over the interval [1, 5]?
-6
-1/2
1/4
1

Sagot :

Answer:

-6

Step-by-step explanation:

Average rate of change = [tex]\frac{f(b)-f(a)}{b-a}[/tex] = [tex]\frac{(17-5^{2)}-(17-1^{2}) }{5-1}[/tex] = -6

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