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Sagot :

From the equations expressed as fractions, having a single variable,

gives;

  1. x = 22.5
  2. x = 2.4
  3. x = 0.8
  4. x = 14
  5. y = 28
  6. b = 6

Which method can be used to find the variables?

[tex]1. \hspace{0.15 cm}\dfrac{4}{9} = \mathbf{\dfrac{10}{x}}[/tex]

By cross multiplying, to clear the fractions, in we have;

4 × x = 10 × 9 = 90

[tex]x = \dfrac{90}{4} = \mathbf{22.5}[/tex]

x = 22.5

[tex]2. \hspace{0.15 cm}\dfrac{5}{2} = \mathbf{\dfrac{6}{x}}[/tex]

5 × x = 6 × 2 = 12

[tex]x = \dfrac{12}{5} = \mathbf{2.4}[/tex]

x = 2.4

[tex]3. \hspace{0.15 cm}\dfrac{5}{2} = \mathbf{\dfrac{2}{x}}[/tex]

5 × x = 2 × 2 = 4

[tex]x = \dfrac{4}{5} = \mathbf{0.8}[/tex]

x = 0.8

[tex]4. \hspace{0.15 cm}\dfrac{21}{27} = \mathbf{ \dfrac{x}{18}}[/tex]

21 × 18 = 27 × x

[tex]x = \dfrac{21 \times 18}{27} = \mathbf{14}[/tex]

x = 14

[tex]5. \hspace{0.15 cm}\dfrac{15}{21} = \mathbf{ \dfrac{20}{y}}[/tex]

15 × y = 20 × 21

[tex]y = \dfrac{20 \times 21}{15} = \mathbf{28}[/tex]

y = 28

[tex]6. \hspace{0.15 cm} \mathbf{\dfrac{26}{b}} = \dfrac{39}{9}[/tex]

26 × 9 = 39 × b

[tex]b = \dfrac{26 \times 9}{39} = \mathbf{ 6}[/tex]

b = 6

Learn more about cross multiplications method here:

https://brainly.com/question/19708346

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