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find two consecutive odd integers that 7 times the smaller integer is 61 more than 2 times the larger integer.

Sagot :

Answer:

x = 13     smaller integer

x + 2 = 15  the other integer

Step-by-step explanation:

x = the smaller integer

x + 2 = the next integer          

7(x) = 61 + 2(x + 2)

7x = 61 + 2x +4

5x = 61 + 4

5x  = 65

x = 13     smaller integer

x + 2 = 15  the other integer

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