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2. How many grams of nitric acid are required to produce 8.75 g dinitrogen monoxide?

4Zn + 10 HNO3 → 4Zn(NO3)2 + N2O + 5 H2O

Sagot :

Answer:

125 grams of HNO3

Explanation:

(8.75g N2O) x (1/44g N2O) x (10mol HNO3) x (63.02g HNO3/ 1mol HNO3) = 125g HNO3

Lhmarianateixeiraidn

In this exercise we have to use our knowledge of chemistry to calculate the final amount in grams for nitrogen monoxide, as:

125 grams of HNO3

Thus, to make these calculations it will be necessary to observe the given equation:

[tex]4Zn + 10 HNO3 \rightarrow 4Zn(NO3)2 + N2O + 5 H2O[/tex]

So after performing the stoichiometry we can perform the calculations as follows:

[tex](8.75g N2O) * (1/44g N2O) *(10mol HNO3) * (63.02g HNO3/ 1mol HNO3)\\ = 125g HNO3[/tex]

See more about stoichiometry at brainly.com/question/9743981

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