Penelopehommmidn
Answered

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Solve for r.
4r – 39 > -43
AND 8x + 31 < 23

Sagot :

Answer:

[tex]4r-39>-43[/tex]

[tex]4r-39+39>-43+39[/tex]

[tex]4r>-4[/tex]

[tex]\frac{4r}{4}>\frac{-4}{4}[/tex]

[tex]\boxed{r>-1}[/tex]

______________________

[tex]8x+31<23[/tex]

[tex]8x+31-31<23-31[/tex]

[tex]8x<-8[/tex]

[tex]\frac{8x}{8}<\frac{-8}{8}[/tex]

[tex]\boxed{x<-1}[/tex]

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