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3 H2SO4(aq) + 2 Al(s) → Al2(SO4)3(aq) + 3 H2(g) How many moles of Al2(SO4)3 are produced when 6.5 moles of aluminum are consumed?

Sagot :

Answer:

3.25 moles

Explanation:

From the equation,   2 moles of Al results in one mole of Al2(so4)3

    6.5 / 2 = 3.25

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