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Find two consecutive negative odd integers whose product is 35?

Sagot :

Answer:36

Step-by-step explanation:

Genmadidn

Step-by-step explanation:

let, a required negative number be x

then it's cnsecutive odd negative. be x+2

now,

[tex] x \times ( x + 2) = 35 \\ or \: \: {x}^{2} \: + 2x = 35 \\ {x}^{2} + 2x = 35 \\ {x}^{2} + 2x - 35 = 0 \\ {x}^{2} + 7x - 5x - 35 = 0 \\ x(x + 7) - 5(x + 7) = 0 \\ (x + 7) (x - 5) = 0 \\ \\ now \: \: \: \: \: \: \:either \: \: x + 7 = 0 \\ x = - 7\\ \\or \: \: \: \: \: (x - 5) = 0 \\ x = 5[/tex]

since ,

we have supposed a negative number ,

,

we need negative odd number so,

x = -7

and it's consecutive number will be x+2

so, it is. -7+2 = -5

hence ,

-7 *and -5 are the required answer.

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