Sandraulochiidn
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solve the following
[tex] log_{10} \: 35 - \: log_{10}17.5 [/tex]
[tex] log_{3} \: 27 + 2 log_{3} \: 9 - log_{3} \: 54[/tex]
[tex] log_{10} \: \frac{1}{2} [/tex]
​

Sagot :

Shaikhaafreen980idn

Answer:

1. [tex] log_{10} \: 35 - \: log_{10}17.5 [/tex]

Answer: 0.331 \: aprox. [/tex]

2. [tex] log_{3} \: 27 + 2 log_{3} \: 9 - log_{3} \: 54[/tex]

Answer: -9 log_{3}

Explanation:

[tex] log_{10}35 - log_{10}17.5 \\ = log_ \frac{35}{17.5} \\ = log_{10}0.5 \\ = log_{5} - log_{10}10 \\ = log_{5 - 1} \\ = 0.669 - 1 \\ = 0.331 \: aprox. [/tex]

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