Find the best answers to your questions with the help of IDNLearn.com's knowledgeable users. Get the information you need from our community of experts who provide accurate and comprehensive answers to all your questions.

Consider the system of equations:
-2x + Ky = 26
13x - 6у = -7
Find all values of k for which the system has exactly one solution. Choose "does not exist" if such a k does not exist.


Sagot :

Answer:

Step-by-step explanation:

First of all, if the system of equations has exactly one solution, then the graph of these two equations will intersect at exactly one point, which means their slopes will be different. If the slopes are the same, there could be infinitely many solutions or no solution.

Rearrange the first equation to solve for slope of  [tex]-2x+ky=26[/tex]

y = (2/k)x + 26/k

The slope is 2/k.

The slope of the second equation is 13/6

as long as 2/k does not equal to 13/6, we have exactly one solution.

SO, the last step:

[tex]\dfrac{2}{k} \neq \dfrac{13}{6}\\[/tex]

[tex]k \neq \dfrac{2}{\dfrac{13}{6}}[/tex]

[tex]k\neq \dfrac{12}{13}[/tex]