Find the best solutions to your problems with the help of IDNLearn.com's expert users. Find the information you need quickly and easily with our comprehensive and accurate Q&A platform.
Answer:
Explanation:
a. CuO+ 2HCl⇒CuCl2+ H2O
b. [tex]n_{CuO}[/tex]= [tex]\frac{4}{80}[/tex]= 0,05 (mol)
⇒[tex]n_{CuCl2}[/tex]= [tex]n_{CuO}[/tex]=0,05 mol
⇒[tex]m_{CuCl2}[/tex]= 0,05×135=6,75 (g)
c. [tex]n_{HCl}[/tex]=2× [tex]n_{CuO}[/tex]=0,1 (mol)
⇒[tex]m_{HCl}[/tex]= 0,1×36,5= 3,65 (g)
⇒[tex]m_{dd HCl}[/tex]= [tex]\frac{m_{HCl}}{10}[/tex]×100=36,5 (g)
⇒ Nồng độ phần trăm dd sau phản ứng= Nồng độ % dd CuCl2=[tex]\frac{m_{CuCl2} }{m_{dd HCl+ m_{CuO} } }[/tex]×100=[tex]\frac{6,75}{36,5+4}[/tex] ×100≈ 16,67%