ItzAakanshi50idn
Answered

IDNLearn.com provides a comprehensive platform for finding accurate answers. Join our knowledgeable community and get detailed, reliable answers to all your questions.

1. An object is accelerated at a rate of 5 m/s²? Find the mass of the object if the force exerted on it is 4 x 10⁵dynes. (Note: 1 N = 1 10⁵ dynes)

Given:
Unknown:
Formula:
Solution:
Final answer:​​

Sagot :

YourHelperAdiidn

Step-by-step explanation:

[tex]\begin{gathered}\frak \red{Given}\:\begin{cases} \:\quad\sf Acceleration \:of \ \: a\:body\:,\:a\:=\:\pmb{\frak{5\:m/s^2\:}}\:\\ \:\quad\sf Force \:Exerted\:on\:a\:body\:,\:F\:=\:\pmb{\frak{\:4\times 10^5\: dynes\:}}\:\end{cases}\\\\\end{gathered}[/tex]

Need To Find : 

  • The mass of a body ?

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀

We're Provided with the , Acceleration (a) , and Force Exerted (F) on a body and , we'll find Mass (m) of the object using the relation

 between Force , Mass & Acceleration  and, that is : 

[tex]\underline {\pmb{\sf \: F\:=\:m\:\times \:a \:}}[/tex]

[tex]\\ \twoheadrightarrow \sf F \:=\:m\:\times \:a[/tex]

[tex]: \rightarrow \sf 4 \:\times 10^5 \:=\:m\:\times \:5\:[/tex]

[tex] \\ \\ \\ \\\twoheadrightarrow \sf 4 \:=\:m\:\times \:5\:\:\Bigg\lgroup \:1 \:N\:=\:1\:\times 10^5\:dynes\:\Bigg\rgroup\\[/tex]

[tex]\\ \twoheadrightarrow \sf 4 \: \:=\:m\:\times \:5\:\\\\\\[/tex]

[tex] \twoheadrightarrow \sf 5m\:=\:4\:\\[/tex]

[tex]\twoheadrightarrow \sf m \cancel{\dfrac{4}{5}}\\\\[/tex]

[tex]\ \twoheadrightarrow \pmb {\underline {\boxed {\purple {\:\frak{ \:m\:\:=\:0.8\:kg\:}}}}}\:\bigstar \: \\[/tex]

[tex]\begin{gathered}\therefore \:\underline {\sf \: Hence,\:Mass\:of\:a\:body\:is\:\pmb{\sf 0.8\:kg\:}\:.}\:\\\\\end{gathered}[/tex]

Somya74idn

Answer:

Tha mass of the body is 0.8 kilo gram (kg).

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Accurate answers are just a click away at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.