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find the value of x
(x+5)+(5-x)+(x+2)=10

Sagot :

Uhohspaghettioooidn

Answer:

x = -2

Step-by-step explanation:

1) Rewrite the equation to remove unnecessary parenthesis: x + 5 + 5 - x + x + 2 = 10

2) Remove the opposite variables: 5 + 5 + x + 2 = 10

3) Calculate the sum of the numbers on the lefthand side: 12 + x = 10

4) Subtract 12 from both sides so that x is by itself: x = 10 - 12

5) Solve the equation on the right, and you get your answer: x = -2

YourHelperAdiidn

Step-by-step explanation:

★Given Term,

[tex]{ \sf{ \green{ { \underline{ (x+5)+(5-x)+(x+2)=10}}}}}[/tex]

★Solution

☼︎Arrange Terms

[tex]...{ \sf{ \longmapsto{(x+5)+(5−x)+(x + 2)=10}}}[/tex]

[tex]...{ \sf{ \longmapsto{(x+5)+(−x+5)+(x+2)=10}}}[/tex]

☼︎Here We Will Eliminate redundant

[tex]...{ \sf{ \longmapsto{x+5)x+5+x+2=10}}}[/tex]

☼︎Add

[tex]...{ \sf{ \longmapsto{x+12−x+x=10}}}[/tex]

☼︎Combine

[tex]...{ \sf{ \longmapsto{1x+12=10}}}[/tex]

☼︎Multiply By 1

[tex]{ \sf {\longmapsto \: {x + 12=10}}}[/tex]

☼︎Subtract  12 from both sides

[tex]{ \sf {\longmapsto \: {x+12−12=10−12}}}[/tex]

☼︎So After Simplifing It We Get,

[tex]{ \underline {\bf {\longmapsto {\boxed{ \sf {\green{x = - 2}}}}}}}[/tex]

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