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the probability that a new microwave oven will stop working in less than 2 years is 0.05. the probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. the probability that a new microwave oven is damaged during delivery is 0.10. given that a new microwave oven is damaged during delivery, what is the probability that it stops working in less than 2 years?

Sagot :

Answer:

0.40

Step-by-step explanation:

0.04 divided by 0.10 = 0.4

Using conditional probability, it is found that there is a 0.4 = 40% probability that it stops working in less than 2 years.

Conditional Probability

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • [tex]P(A \cap B)[/tex] is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Damaged during delivery.
  • Event B: Stops working in less than 2 years.

0.1 probability of being damaged during delivery, hence [tex]P(A) = 0.1[/tex].

0.04 probability of being damaged during delivery and stop working, hence [tex]P(A \cap B) = 0.04[/tex]

The conditional probability is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.04}{0.1} = 0.4[/tex]

0.4 = 40% probability that it stops working in less than 2 years.

A similar problem is given at https://brainly.com/question/14398287