IDNLearn.com provides a collaborative environment for finding accurate answers. Ask your questions and receive reliable and comprehensive answers from our dedicated community of professionals.
Sagot :
Answer:
25
Step-by-step explanation:
We'll compare it with the study of sets, the most noticeable operation of which is:
- n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
where,
n(A ∪ B) is the Union Set, i. e, the set that contains all the elements
n(A) is a subset of the Union Set
n(B) is another subset of the Union Set, and
n(A ∩ B) is the Intersection Set ,i.e, the set contains common elements from both A and B sets.
In the question:
- n(A ∪ B) = ? (the total number of students in the class who are into the above mentioned sports)
Let set A contains the students who play basketball and set B, the students who play Volleyball.
- n(A) = 25
- n(B) = 20
10 students play both of them, i. e.,
- n(A ∩ B) = 10 (as 10 students have common sports - Volleyball and Basketball)
Using the above operation:
=> n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
=> n(A ∪ B) = 25 + 20 - 10
=> n(A ∪ B) = 35
Final Step to the Answer:
The total number of students in the class
= students into the given sports + students who don't play any of them
- Total number of students in the class is 60
- Total number fo students playing basketball and volleyball is 35
The students who play neither = 60 - 35
= 25
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.