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Sagot :
Answer:
25
Step-by-step explanation:
We'll compare it with the study of sets, the most noticeable operation of which is:
- n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
where,
n(A ∪ B) is the Union Set, i. e, the set that contains all the elements
n(A) is a subset of the Union Set
n(B) is another subset of the Union Set, and
n(A ∩ B) is the Intersection Set ,i.e, the set contains common elements from both A and B sets.
In the question:
- n(A ∪ B) = ? (the total number of students in the class who are into the above mentioned sports)
Let set A contains the students who play basketball and set B, the students who play Volleyball.
- n(A) = 25
- n(B) = 20
10 students play both of them, i. e.,
- n(A ∩ B) = 10 (as 10 students have common sports - Volleyball and Basketball)
Using the above operation:
=> n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
=> n(A ∪ B) = 25 + 20 - 10
=> n(A ∪ B) = 35
Final Step to the Answer:
The total number of students in the class
= students into the given sports + students who don't play any of them
- Total number of students in the class is 60
- Total number fo students playing basketball and volleyball is 35
The students who play neither = 60 - 35
= 25
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