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Answer:
0.11M
Explanation:
What is the Molarity of a Ca(OH)2 solution if 30.0mL of
the solution is neutralized by 26.4mL of 0.25M HCI solution?
1L (1000 ml) of the HCl contains 0.25 moles of H ion
26.4 ml contains ( 26.4 X0.25/1000) moles of H ion ion
=0.0066 moles H ion
2HCl +Ca (OH)2-----> 2H2O +CaCl2
SO 2 H IONS NEUTRALIZE 1 Ca(OH)2 MOLECULE
00066 moles H ion neutralize 0.0033 moles Ca(OH)2
the 0.0033 moles are distributed over 30 ml, so the concentration of the
Ca(OH)2 IS 0,0033/(30/1000) =0.11 moles/liter or 0.11M