Wadfamidn
Answered

Join IDNLearn.com and start exploring the answers to your most pressing questions. Get comprehensive answers to all your questions from our network of experienced experts.

Use the graph to determine which one of the three statements below is a lie.

The average rate of change between [0,4] is positive
The average rate of change between [-3, 4] is 7.
The average rate of change between [0,4] is ¾.

Explain using one or two sentences why it is a lie or how to make it a true statement.

Use The Graph To Determine Which One Of The Three Statements Below Is A Lie The Average Rate Of Change Between 04 Is Positive The Average Rate Of Change Between class=

Sagot :

Altavistardidn

Answer:

Step-by-step explanation:

One formula for "average rate of change" is

               f(b) - f(a)

a. r. c. = -------------------  = (increase in y) / (increase in x

                   b - a

In the case of this particular function, a = 0, b = 4, and the related y-values are f(a) = f(0) = -3, f(b) = f(4) = 0, and so the average rate of change of this function on (0, 4) is

               f(4) - f(0)          0 - (-3)

a. r. c. = ---------------- = --------------- = +3/4

                   4 - 0                  4

Therefore, "The average rate of change between [0,4] is positive" is true.

               

               f(4) - f(-3)          0 - (0)

a. r. c. = ---------------- = --------------- = 0 (not 7)

                   4 - 0                  4

Therefore, "The average rate of change between [-3,4] is positive" is false.  The average r. of c. is actually 0.  (Again, see above).

From above,

               f(4) - f(0)          0 - (-3)

a. r. c. = ---------------- = --------------- = +3/4    This is true

                   4 - 0                  4

Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.