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Answered

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How many solutions are there for the system of equations containing y = x-5 and
2x - 2y = 8, and why?

Sagot :

Polyblockidn

Answer:

None, because 0 cannot equal 1.

Step-by-step explanation:

y = x - 5

2x - 2y = 8

First let's solve for y in the bottom equation

Subtract 2x form both sides

2x - 2y = 8

- 2x         - 2x

-2y = 8 - 2x

Divide both sides by -2

-2y/-2 = (8 - 2x)/-2

y = x - 4

Now substitute the y's in both equations

x - 4 = x - 5

Move like terms to one side by adding 4 to both sides

x - 4 = x - 5

 + 4      + 4

x = x - 1

Subtract x from both sides

x = x - 1

- x - x

0 = 1

Zero cannot equal one, meaning this system of equations is invalid and has no solutions.

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