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Triangle ABC is rotated 45° about point X, resulting in triangle EFD. Triangle A B C is rotated 45 degrees about point X to form triangle E F D. The lengths of sides A C and D E are congruent, the lengths of sides A B and E F are congruent, and the lengths of sides D F and C B are congruent. If EF = 4. 2 cm, DF = 3. 6 cm, and DE = 4. 5 cm, what is CB? 3. 3 cm 3. 6 cm 4. 2 cm 4. 5 cm.

Sagot :

Answer:

3.6 cm

Explanation:

Here, triangle ABC is rotated about point X which results in triangle EFD. Since triangle ABC is rotated it retains its shape and dimensions. This means that triangle ABC is parallel to triangle EFD ie, ABC≈EFD, also both dimensions will be congruent.

Thus

AB = EF

BC = FD

AC = ED

CB = DF

BA = FE

CA = DE

Since length of side DF = length of side CB, and DF = 3.6 cm. Therefore, CB = DF = 3.6 cm

Length of CB = 3.6 cm

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