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The pressure of a gas at 35.6oC is 114.3kPa. What is the pressure when the temperature drops to 17.3oC? Assume constant volume.

Sagot :

Purplefox1212idn

Answer:

107.5252955kPa or 108kPa

Explanation:

Use Gay Lussac's Law, P1/T1 = P2/T2

Manipulate the equation: P2 = P1*T2/T1

Change C to K: 35.6C = 308.75K and 17.3 = 290.45K

Input the values: P2 = (114.3kPa)(290.45K)/308.75K

P2= 107.5252955kPa

You probably want to round to 3 sig figs, so 108kPa

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