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If 79.5 mol of an ideal gas is at 8.91 atm at 47.20 °C, what is the volume of the gas?

Sagot :

Purplefox1212idn

Answer:

235L

Explanation:

PV =nRT

V = nRT/P

47.20 °C is 320.35K

V = (79.5 mol)(0.0821 atm•L/mol•K)(320.35K)/8.91atm

V = 234.6698577L

Round to 3 sig figs: 235L

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