User1828281idn
Answered

IDNLearn.com is your go-to platform for finding reliable answers quickly. Ask your questions and get detailed, reliable answers from our community of knowledgeable experts.

given that R=0.0821 (L•atm) / (mol•K) how many moles must be in a 2L container at 1.8 atmospheres with a temperature of 270K

Sagot :

Eduard22slyidn

The number of mole in the container at 1.8 atm with a temperature of 270 K is 0.162 mole.

From the question given above, the following data were obtained:

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) = 2 L

Pressure (P) = 1.8 atm

Temperature (T) = 270 K

Number of mole (n) =?

Using the ideal gas equation, we can obtain the number of mole in the container as illustrated below:

PV = nRT

1.8 × 2 = n × 0.0821 × 270

3.6 = n × 22.167

Divide both side by 22.167

n = 3.6 / 22.167

n = 0.162 mole

Therefore, the number of mole in the container is 0.162 mole

Learn more: https://brainly.com/question/9731218

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.