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Which statement explains how to correct the error that was made?
O The subtraction property of equality should have been applied to move m to the other side of the equation.
O The multiplication property of equality should have been applied in the last step.
The division property of equality should have been used to divide by k instead of m.
O The square root property should have been applied to both complete sides of the equation instead of to select
variables.

Which Statement Explains How To Correct The Error That Was Made O The Subtraction Property Of Equality Should Have Been Applied To Move M To The Other Side Of T class=

Sagot :

Solving for v in the given equation is performed by making v the equation's

subject.

Response:

The statement that describes where the error was made is option;

  • The square root property should have been applied to both complete sides of the equation instead of to select variables.

Method for solving for v in the given equation;

v can be solved for from the  given expression as follows;

[tex]\displaystyle k = \mathbf{\frac{1}{2} \cdot m \cdot v^2}[/tex]

[tex]\displaystyle k \div m = \mathbf{\left(\frac{1}{2} \cdot m \cdot v^2 \right) \div m}[/tex]

[tex]\displaystyle \frac{k}{m} \times 2 = \left( \frac{1}{2} \cdot v^2 \right) \times 2[/tex]

[tex]\displaystyle \frac{2 \cdot k}{m}= \mathbf{v^2}[/tex]

Taking the square root of both sides of the equation gives;

[tex]\pm \sqrt{\displaystyle \frac{2 \cdot k}{m}} = \mathbf{\sqrt{v^2}}[/tex]

Therefore;

[tex]\displaystyle \pm \sqrt{\frac{2 \cdot k}{m} } = v[/tex]

Therefore, the error was made in the step, [tex]\displaystyle \pm \frac{2 \cdot \sqrt{k} }{m} = \sqrt{v^2}[/tex] , which is by

applying the square root property was applied to only some of the

variables on the left hand side of the equation, rather than the combined

expression on the left hand side of the equation.

Learn more about making a variable the subject of the formula here:

https://brainly.com/question/8481791

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