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Given A = {x ∈ ℤ : 4|x} and B = {x ∈ ℤ : 2|x}. Prove A ⊆ B.

Sagot :

Let a ∈ A. Then a is some integer that is divisible by 4, so we can write a = 4k for some integer k.

We can simultaneously rewrite a as a = 2•2k, so 2 clearly divides a, which means a ∈ B as well.

Therefore A ⊆ B.