Karsene765idn
Answered

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A person has a bag of coins.

4/13 of the coins are pennies

1/4 of the coins that are not pennies, are nickels

The rest are dimes. If there is $8.10 in dimes, how much total money is in the bag of coins?

Sagot :

Srinidhiqueenidn

Answer:

$15.6

Step-by-step explanation:

First, let's assume that x is the total money in the bag of coins.

1. x = total money

4/13 of the coins are pennies, so 4/13 of x equals to the number of pennies.

4/13(x) = P (pennies)

What is left that is not pennies is 9/13(x). And out of these, 1/4 are nickels. Which means:

1/4(9/13[x]) = N (nickels)

If 1/4 of the remaining are nickels, then 3/4 are dimes. So:

3/4(9/13[x]) = $8.10 (dimes' value)

After calculating the one with the value:

27/52(x) = $8.10

27x = $8.10 times 52

x = ($8.10 times 52)/27

x = 52 x $0.3

x = $15.6

Ans. The value of the bag of coins is $15.6

Angerymarshmelloidn
The answer is $15.06
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