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Newton's second law allows finding the result for the comparison of the rise and fall times of the block on the ramp is:
- The acceleration of the two processes is the same, if the initial velocity is equal, the times are equal.
Newton's second law establishes a relationship between the net force, the masses and the acceleration of the bodies.
∑ F = m a
Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.
The reference system is a coordinate system with respect to which the forces are drawn, in the attached we can see a free body diagram of the block going up and down the ramp, in this case the x axis is parallel to the ramp and the y axis it is perpendicular.
Let's use trigonometry to find the components of weight.
sin θ = [tex]\frac{W_x}{W}[/tex]
cos θ = [tex]\frac{W_y}{W}[/tex]
Wₓ = W sin θ
[tex]W_y[/tex] = W cos θ
Let's write Newton's second law for each axis.
Case 1. block slides down.
x- axis
Wₓ = ma
mg sin θ = ma
a = g sin θ
Case 2. block rises
X axis
- Wₓ = m a
- m gsin θ = a
a = - g sin θ
We can see that the acceleration is the same in two two cases, if the block has the same initial speed, the rise and fall time is the same.
y = v₀ t - ½ a t²
y = ½ a t²
In conclusion using Newton's second law we can find the result for the comparison of the rise and fall times of the block on the ramp is:
- The acceleration is the same, if the initial velocity is the same, the times of going up and down are the same.
Learn more here: brainly.com/question/15760805
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