Answered

Join the IDNLearn.com community and start finding the answers you need today. Find the solutions you need quickly and accurately with help from our knowledgeable community.

Imagine that you have a bag with 2 red blocks, 3 blue blocks, 4 green blocks, and 1 yellow block inside.
You plan to make one draw from the bag.

A Find the probability of getting a green block or a blue block. p(blue or green)=??? (Do not Simplify any Fraction)

you plan on making two draws from the bag (replacing the first)
B Find the probability of getting a green block then a blue block. (order matters) p(green then blue) = ???

C Which is more likely to happen? A or B? Write the letter down.

Sagot :

739086idn

Answer:

it’s B

Step-by-step explanation:

Darth21idn

Answer:

Information given

3 blue

2 red

4 green

1 yellow

Total= 10

For (1)  for the probability of a green OR blue blocks you jsut gotta add up green and blue. 4+3=7 And 10 blocks in total so 7/10 chance

For (b) you find the probability of a green which is 4/10 and then a blue which is 3/10. So assumingg you draw twice you have 4/10*3/10 which is 12/100 chance of getting that order.

Well of course b is most likely to happen because its the most Chances.

7/10 > 12/100

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.