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If an object falls from rest and lands 3.2 seconds later, how many
meters did it fall


Sagot :

Answer:

50.2 meters

Explanation:

When an object falls, it goes a distance d in time t according to the formula:

[tex]d=\frac{1}{2}*g*t^{2}[/tex]

d is the distance in meter, g is the acceleration due to gravity with the value of 9.8[tex]m/s^{2}[/tex] , t is the time in seconds

Therefore, [tex]d = \frac{1}{2}*9.8*(3.2)^{2}[/tex]

d= 50.176 ≈ 50.2m