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Mrs. Jones invited her husband, Lester, on her weekly slide down the waxed hallway. Mr. Jones weighs 850. N and the coefficient of friction between his socks and the floor is 0.120. What is the magnitude of the force of friction the opposes his motion?

Sagot :

Trancescientidn

Explanation:

We know that [tex]f = \mu N,[/tex] where N is the normal force and [tex]\mu[/tex] is the coefficient of friction. In this case, Mr. Jones's weight is the normal force therefore, the frictional force on Mr. Jones is

[tex]f = (0.120)(850\:\text{N}) = 102\:\text{N}[/tex]

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