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Find the following for the nth term of the following geometric sequence, as an expression of n:

3, 15, 75, 375

Sagot :

Hi1315idn

Answer:

[tex]15^{n-1}[/tex]

Step-by-step explanation:

First , Let's find the common ratio of this sequence.

[tex]\frac{15}{3}=5\\\frac{75}{15} = 5\\\frac{375}{75} = 5[/tex]

SO,

r = 5

Now let's use this formula to find the n th term

[tex]T_n = ar^{n-1}[/tex]

Here,

a = first term

r = common ratio

Let's find,

[tex]T_n = 3*5^{n-1}[/tex]

[tex]T_n =15^{n-1}[/tex]

Therefore,

the n th term is,

[tex]15^{n-1}[/tex]

Hope this helps you.

Let me know if you have any other questions :-)

Answer:

[tex]a_{n}[/tex] = 3[tex](5)^{n-1}[/tex]

Step-by-step explanation:

There is a common ratio between consecutive terms , that is

15 ÷ 3 = 75 ÷ 15 = 375 ÷ 75 = 5

This indicates the sequence is geometric with nth term

[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]

where a₁ is the first term and r the common ratio

Here a₁ = 3 and r = 5 , then

[tex]a_{n}[/tex] = 3 [tex](5)^{n-1}[/tex]

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