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The first four terms of a sequence are 5,-3,-11,-19. Which of the following is an equation for the nth term of the sequence?

an=8n−3A sub n is equal to 8 n minus 3

an=n−4A sub n is equal to n minus 4

an=−8n+13A sub n is equal to negative 8 n plus 13

an=−8n−8

Sagot :

Answer:

Step-by-step explanation:

-3-5=-8

-11-(-3)=-11+3=-8

-19-(-11)=-19+11=-8

it is an A.P. and c.d.=-8

so nth term is

an=a1+(n-1)d

an=5-(n-1)(-8)

an=5+8n-8

an=8n-3

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