Answer: [tex]\bf \dfrac{9}{14}[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{2-\dfrac{4}{3x} }{2+\dfrac{4}{3x} } =\frac{2}{5} \\\\\\ \frac{\dfrac{6x-4}{\boldsymbol{3x}} }{\dfrac{6x+4}{\boldsymbol{3x}} } =\frac{2}{5} \ \ ; \ \ x\neq 0 \\\\\\ \frac{6x-4}{6x+4}=\frac{2}{5} \\\\\\ 5(6x-4)=2(6x+4 )\\\\30x-20=12x+8 \\\\ 30x-12x=8+20 \\\\18x=28 \\\\ x=\frac{14\cdot 2}{9\cdot 2} \\\\\\ \boxed{x=\frac{14}{9 } }[/tex]
