Answered

For all your questions, big or small, IDNLearn.com has the answers you need. Discover in-depth and reliable answers to all your questions from our knowledgeable community members who are always ready to assist.

100.mL of a .795 M solution of KBr is diluted to 500.mL. what is the new concentration of the solution?

Sagot :

Answer:

0.159 M

Explanation:

convert from mL to L then use the equation:

M1V1 = M2V2

rearrange to find M2

[tex]\frac{M1V1}{V2} = M2[/tex]

[tex]\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M[/tex]

Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Thank you for choosing IDNLearn.com for your queries. We’re here to provide accurate answers, so visit us again soon.