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Answer:
Explanation:
Well, which is it, level ground or sloping upward at a ratio of 1 m rise for every 5 m of run?
I will ASSUME you mean the shadow is 32 m long as measured along the 1:5 slope and the sun is 55° above the horizon.
The ground slope to horizon is
arctan (1/5) = 11.31°
The "top" end of the shadow is above the tower base by
32sin11.31 = 6.2757 m
The "top" end of the shadow is a horizontal distance from the tower base of
32cos11.31 = 31.3786 m
The tower height above the "top" of the shadow is
h = 31.3786tan55 = 44.8132 m
so the tower height is
44.8132 + 6.2757 = 51.0889 = 51 m