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Sagot :
Answer:
cost of admission for each child was $4.00, and each adult was $25.33
Step-by-step explanation:
When solving questions like these , I like to break down the problem so I understand it better.
Let x ---> cost of the admission for each child
Y ---------> cost of the admission for each adult
9x+3y = 112 ---> equation A
8x + 3y = 108 ---> equation B
Subtract B from A
9x+3y=112
-8x+3y = 108
x = 112-108
x = 4
Find value of y by substituting value of x into equation
9(4)+3y=112
Solve for y
36+3y = 112
3y = 112=36
3y = 76
y = 25.33
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