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A chemical company makes two brands of antifreeze. The first brand is 40% pure antifreeze, and the second brand is 60% pure antifreeze. In order to obtain 180 gallons of a mixture that contains 55% pure antifreeze, how many gallons of each brand of antifreeze must be used?

First brand =
Second Brand=

Sagot :

Answer:

Step-by-step explanation:

Let x be the portion of 60%

180 - x is the portion of 40%

0.60x + 0.40(180 - x) = 0.55(180)

0.60x + 72 - 0.40x = 99

0.20x = 27

x = 135

180 - 135 = 45

First brand = 45 gallons of 40%

Second Brand = 135 gallons of 60%

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